bŁAGAM O POMOC :
POLE TRAPEZU O PODSTAWACH DŁUGOŚCI 13 cm i 25cm wynosi 323cm2 . Oblicz wysokość tego trapezu
wzór na pole trap. P= 1/2 x h x (a+b) = 323 cm2
P = 1/2 x h x (25+13) = 323cm2
P = h x 19 cm = 323 cm2
323 cm2 : 19 cm = 17 cm
h = 17 cm
P=(a+b):2*h
P=323cm²
a=13cm
b=25cm
h=?
323cm²=(13cm+25cm):2*h
323cm²=38cm:2*h
323cm²=19cm *h
h=323cm²:19cm
h=17cm
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
wzór na pole trap. P= 1/2 x h x (a+b) = 323 cm2
P = 1/2 x h x (25+13) = 323cm2
P = h x 19 cm = 323 cm2
323 cm2 : 19 cm = 17 cm
h = 17 cm
P=(a+b):2*h
P=323cm²
a=13cm
b=25cm
h=?
323cm²=(13cm+25cm):2*h
323cm²=38cm:2*h
323cm²=19cm *h
h=323cm²:19cm
h=17cm