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1+a=b/c*1-a
1+a=(b-a)*c
a=bc-ac-1
ac+a=bc-1 /c
2a=b-1/c /:2
a=b/2-(1/c)/2
2) a/(a-t) = b/(b-t)
1-a/t=1-b/t /*t
t-a=t-b
-a=t-b-t
-a=-b
a=b
a=(b:c)-1
*-razy (mnożenie)
2.
b*a=(b-t)*(a-t)
*-razy (mnożenie)