September 2018 1 128 Report
Ayúdenme a resolver los tres métodos reducion sustitución y ijualacion

a) 3x+2y+z=1
5x+3y+4z=2
x+y-z=1


b) 5x-3y-z=1
x+4y-6z=-1
2x+3y+4z=9

c) 2x-y+2z=6
3x+2y-z=4
4x+3y-3z=1

d) 2x-3y+4z=11
x+y-2z=-2
-x+y-z=1

e) x+y+z=1
5x+3y+4z=2
3x+2y+z=1

f ) x-y+z=3
2y+3z=15
3x+y =12

j) x+y-2y=9
2x-y+4z=4
ex-y+6z=-1

k) x+y+z=6
x +z=4
y+z=5

m) x+y+z=2
2x+3y+5z=11
x-5y+6z=29









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