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(n-5)(n+1)=0
n-5=0. y. n+1=0
n=5. y. n=-1
dos soluciones
b^2-9b+18=0
(b-6)(b-3)=0
b-6=0. y. b-3=0
b=6. y. b=3
dos soluciones
saludos
n -5
n +1
-5n+n = -4n
(n-5)(n+1) = 0
n-5 = 0 n+1 = 0
n = 5 n = -1
CS = (-1;5)
b -6
b -3
-6b-3b = -9b
(b-6)(b-3) = 0
b-6=0 b-3 =0
b=6 b=3
CS = (3; 6)