Respuesta:
nose
Explicación paso a paso:
pero espero q lo puedas solucionar tu tarea
[tex] \frac{x² + y²}{2x + 2y} = \frac{(3)^{2} + {(1)}^{2} }{2(3) + 2(1)} = \frac{9 + 1}{6 + 2} = \frac{10}{8} = 1,25[/tex]
[tex]a² + b² + c²-2ab-2cb-2ac = {(1)}^{2} + {(2)}^{2} + {(3)}^{2} - 2(1)(2) - 2(3)(2) - 2(1)(3) = 1 + 4 + 9 - 4 - 12 - 6 = 14 - 22 = - 8[/tex]
[tex] \frac{x + y + z}{ {x}^{2} + 3xy - {z}^{2} } = \\ \frac{( - 2) +(3) + (2) }{( - 2)^{2} + 3( - 2)(3) - {(2)}^{2} } = \\ \frac{ - 2 + 3 + 2}{ 4 - 18 - 4} = \frac{ - 2 + 5}{4 - 22} = \\ \frac{ +3}{ - 18} = - 0,16[/tex]
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Respuesta:
nose
Explicación paso a paso:
pero espero q lo puedas solucionar tu tarea
Explicación paso a paso:
[tex] \frac{x² + y²}{2x + 2y} = \frac{(3)^{2} + {(1)}^{2} }{2(3) + 2(1)} = \frac{9 + 1}{6 + 2} = \frac{10}{8} = 1,25[/tex]
[tex]a² + b² + c²-2ab-2cb-2ac = {(1)}^{2} + {(2)}^{2} + {(3)}^{2} - 2(1)(2) - 2(3)(2) - 2(1)(3) = 1 + 4 + 9 - 4 - 12 - 6 = 14 - 22 = - 8[/tex]
[tex] \frac{x + y + z}{ {x}^{2} + 3xy - {z}^{2} } = \\ \frac{( - 2) +(3) + (2) }{( - 2)^{2} + 3( - 2)(3) - {(2)}^{2} } = \\ \frac{ - 2 + 3 + 2}{ 4 - 18 - 4} = \frac{ - 2 + 5}{4 - 22} = \\ \frac{ +3}{ - 18} = - 0,16[/tex]