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2x² - 18 = 2( x² - 9) = 2(x+3)(x-3)
La segunda se complica pero puede ser
x³ + x² -2 = x³ + x² -1 -1 y asociamos
(x³ - 1) + (x² - 1) = (x - 1) ( x² +x+1) + (x-1)(x+1) aqui x-1 es factor común
(x - 1 ) [( x² + x +1) + (x+1)]