Question

At Least...Ayo soal gmpng no 3 Master :)

Answer 1

ΔTb = [massa glukosa/mr] x [1000/massa air] x Kf
100,65 - 100 = [g/180] x [1000/100] x 0,52
0,65 = [g/180] x 5,2
g = [0,65 x 180] / 5,2

diperoleh massa glukosa sebesar 22,5 gram

Answer 2

ΔTb = [massa glukosa/mr] x [1000/massa air] x Kf 100,65 - 100 = [g/180] x [1000/100] x 0,52 0,65 = [g/180] x 5,2 g = [0,65 x 180] / 5,2