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Misal massa Al = massa Zn = X
Maka mol Al = X/27
Karena perbandingan koefisien, mol Al = 3 mol H2 = X/9 mol
Maka mol Zn= X/65
Karena perbadingan koefisen, mol Zn = mol H2 = X/65 mol
Jika pada tekanan dan suhu yang sama maka:
n1/V1=n2/V2
(X/9)/V1 = (X/65)/V2
X/9 v1 = X/ 65 V2
9V1= 65V2
Maka perbandingan volumenya:
V1 : V2 = 65 : 9