1a
There exists a, b, c ≠ 0 such that
One of them is, a = -2, b = -1, c = 1
This shows that the given set of vectors are linearly dependent hence not a basis of the vector space
1b
Set the two vectors into the form of 3 x 2 Row-Echelon matrix (picture above)
We get that there's only 2 pivot colums which shows that the dimension of the matrix is 2, instead of 3.
This clearly shows that the given set of vectors don't span the space hence not a basis of the vector space
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1a
There exists a, b, c ≠ 0 such that
One of them is, a = -2, b = -1, c = 1
This shows that the given set of vectors are linearly dependent hence not a basis of the vector space
1b
Set the two vectors into the form of 3 x 2 Row-Echelon matrix (picture above)
We get that there's only 2 pivot colums which shows that the dimension of the matrix is 2, instead of 3.
This clearly shows that the given set of vectors don't span the space hence not a basis of the vector space