October 2018 1 38 Report
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x=12 y=15 z=10

1)3x + 4y

2)6z + (x+y)

3)(x+y+7z) +(¿?+2z)

4)(2x+y+6z) + (¿?+2y)

5)6y + (¿?+x)

6)(2x+y)+(4z)


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