October 2018 1 36 Report
Alguien me podria ayudar?

x=12 y=15 z=10

1)3x + 4y

2)6z + (x+y)

3)(x+y+7z) +(¿?+2z)

4)(2x+y+6z) + (¿?+2y)

5)6y + (¿?+x)

6)(2x+y)+(4z)


More Questions From This User See All

Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.