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A B C
2x+y+3=0 pendiente m2=-A/B ;m= -2/1;m=-2
TangФ=(m2-m1)/(1+m2*m1)
TangФ=(-2-3)/(1+(-2)(3))
TangФ=-5/-5
TangФ=1
Ф=tan-1(1)
Ф=45° Respuesta