ALGEBRA: Suma trzech kolejnych liczb parzystych wynosi 42. Jakie to liczby?
n ---------liczba parzysta
nastepna to n+2
i n+4
n+n+2+n+4 = 42
3n = 42-6
3n = 36
n = 12
n+2 = 14
n+4 = 16
sprawdzam
12+14+16 = 42
Odpowiedź w załączniku
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n ---------liczba parzysta
nastepna to n+2
i n+4
n+n+2+n+4 = 42
3n = 42-6
3n = 36
n = 12
n+2 = 14
n+4 = 16
sprawdzam
12+14+16 = 42
Odpowiedź w załączniku