Alas sebuah prisma berbentuk belah ketupat dengan panjang diagonalnya 24 cm dan 10 cm. jika tinggi prisma 20 cm, hitunglah luas permukaan prisma tersebut!
nabbb
Luas prisma = 2luas alas x keliling alas x t luas alas x 2 = 2 ( 24 x 10 :2 ) = 240 cm Keliling alas = 4s s = √5²+12² = 13 4 x 13 = 52 = 240 + 52 X20 = 1280
liwonsubagyo
L. alas = d1 x d2 2 = 24 x 10 2 = 120cm² sisi =√ 12² + 5² = √ 144 + 25 = √169 = 13cm K.alas = 4 x s = 4 x 13 = 52cm L.permukaan = K.a x t + 2 x L.a = 52 x 20 + 2 x 120 = 1.040 + 240 = 1.280cm²
luas alas x 2 = 2 ( 24 x 10 :2 )
= 240 cm
Keliling alas = 4s
s = √5²+12² = 13
4 x 13 = 52
= 240 + 52 X20
= 1280
2
= 24 x 10
2
= 120cm²
sisi =√ 12² + 5²
= √ 144 + 25
= √169
= 13cm
K.alas = 4 x s
= 4 x 13
= 52cm
L.permukaan = K.a x t + 2 x L.a
= 52 x 20 + 2 x 120
= 1.040 + 240
= 1.280cm²