Question

Akar akar dar 2x2-3-x+4=0 adalah x1 dan x2.maka akar akar (x1+2)( x2 +2) adalah

Answer 1

2x² - 3x + 4 = 0
a = 2
b = -3
c = 4
x₁+x₂ = -b/a = -(-3) / 2 = 3/2
x₁.x₂ = c/a = 4/2 = 2

(x₁ + 2) (x₂ + 2) = x₁.x₂ + 2x₁ + 2x₂ + 4
                       = x₁.x₂ + 2 (x₁+x₂) + 4
                       = 2 + 2 (3/2) + 4
                       = 2 + 3 + 4
                       = 9

semoga membantu ya :)