P(-2) = 2, P(3) = -3
x²-x-6 = (x+2)(x-3)
misalkan sisa pembagian P(x) dengan x²-x-6 disebut ax+b
ax+b = sisa <= x = -2, sisa = 2
-2a+b = 2
b = 2a+2
ax+b = sisa <= x = 3, sisa = -3
3a+b = -3 <= b = 2a+2
3a + 2a+2 = -3
5a = -5
a = -1
b = 2.(-1)+2
b = 0
maka sisanya adalah -x (D)
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P(-2) = 2, P(3) = -3
x²-x-6 = (x+2)(x-3)
misalkan sisa pembagian P(x) dengan x²-x-6 disebut ax+b
ax+b = sisa <= x = -2, sisa = 2
-2a+b = 2
b = 2a+2
ax+b = sisa <= x = 3, sisa = -3
3a+b = -3 <= b = 2a+2
3a + 2a+2 = -3
5a = -5
a = -1
b = 2.(-1)+2
b = 0
maka sisanya adalah -x (D)
Jawab:
Penjelasan dengan langkah-langkah: