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Mengingat log 13 antara log 12 dan log 14
x1 = 12
y1 = log 12 = 2 log 2 + log 3 = 2(0,3)+0,48 = 0,6 + 0,48 = 1,08
x2 = 14
y2 = log 14 = log 2 + log 7
Karena log 7 antara log 6 dan log 8, maka
Log 7 = (0,9-0,78)(7-6)/(8-6) + 0,78
= 0,12/2 + 0,78 = 0,06 + 0,78 = 0,84
y2 = 0,3 + 0,84 = 1,14
Log 13 = (1,14-1,08)(13-12)/(14-12) + 1,08 = 0,06/2 + 1,08 = 0,03 + 1,08 = 1,11