Question

Ada yang bisa? pakai cara..
2^2x-1 - 9 . 2^x-2 + 1 = 0

Answer 1

2^(2x-1)- 9 . 2^(x-2 )+ 1 = 0
1/2 . (2^x)^2 - 9 . 1/2^2 . 2^x + 1 = 0
kedua ruas dikali 4, get
2(2^x)^2 - 9. 2^x + 4 = 0
(2 . 2^x - 1)(2^x - 4) =0
2 . 2^x - 1 = 0 atau 2^x - 4 = 0
2 . 2^x = 1 atau 2^x = 4
2^x = 1/2 atau 2^x = 2^2
solusi x = -1 atau x = 2