Question

Ada yang bisa bantu???

Ps. No 14 jawab sebisanya ya maaf opsi jawabannya kepotong​

Answer 1

Penjelasan dengan langkah-langkah:

13] x = 2

x² + (t - 5) x + t² - 18 = 0

2² + (t - 5) . 2 + t² - 18 = 0

4 + 2t - 10 + t² - 18 = 0

t² + 2t - 24 = 0

(t + 6) . (t - 4) = 0

t + 6 = 0

t = -6

t - 4 = 0

t = 4

x² + (-6 - 5) x + (-6)² - 18 = 0

x² - 11x + 36 - 18 = 0

x² - 11x + 18 = 0

(x - 9) . (x - 2) = 0

x - 9 = 0

x = 9

x - 2 = 0

x = 2

x² + (4 - 5) x + 4² - 18 = 0

x² - x + 16 - 18 = 0

x² - x - 2 = 0

(x - 2) . (x + 1) = 0

x - 2 = 0

x = 2

x + 1 = 0

x = -1

9 atau -1

14] p² - 3p - 10 = 0

p² - 3p = 10

(p - 3/2)² - (3/2)² = 10

(p - 3/2)² - 9/4 = 10

(p - 3/2)² = 40/4 + 9/4

p - 3/2 = +- √(49/4)

p = 3/2 +- 7/2

p1 = 3/2 + 7/2

p1 = 10/2

p1 = 5

p2 = 3/2 - 7/2

p2 = -4/2

p2 = -2

Kode Kategorisasi : 9.2.9

Kelas 9

Pelajaran 2 - Matematika

Bab 9 - Persamaan Kuadrat