3y² - 2y - 2 = 0
a = 3
b = -2
c = -2
y1,2 =(-b ± √b²-4ac)/2a
= (-(-2) ± √(-2)²-4×3×-2)/2(3)
= (2 ± √4-(-24))/6
= (2 ± √28)/6
= (1 ± √7)/3
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3y² - 2y - 2 = 0
a = 3
b = -2
c = -2
y1,2 =(-b ± √b²-4ac)/2a
= (-(-2) ± √(-2)²-4×3×-2)/2(3)
= (2 ± √4-(-24))/6
= (2 ± √28)/6
= (1 ± √7)/3