Penjelasan dengan langkah-langkah:
22] f(x) = x² - bx - 12
(-2, 0)
f(-2) = 0
(-2)² - b . (-2) - 12 = 0
4 + 2b - 12 = 0
2b - 8 = 0
2b = 8
b = 8/2
b = 4
Jawabannya B
23] f(x) = x² - x + c
(-5, 0)
f(-5) = 0
(-5)² - (-5) + c = 0
25 + 5 + c = 0
30 + c = 0
c = -30
x² - x - 30 = 0
(x - 6) . (x + 5) = 0
x - 6 = 0
x = 6
(6, 0)
Jawabannya C
Kode Kategorisasi : 10.2.5
Kelas 10
Pelajaran 2 - Matematika
Bab 5 - Persamaan dan Fungsi Kuadrat
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Penjelasan dengan langkah-langkah:
22] f(x) = x² - bx - 12
(-2, 0)
f(-2) = 0
(-2)² - b . (-2) - 12 = 0
4 + 2b - 12 = 0
2b - 8 = 0
2b = 8
b = 8/2
b = 4
Jawabannya B
23] f(x) = x² - x + c
(-5, 0)
f(-5) = 0
(-5)² - (-5) + c = 0
25 + 5 + c = 0
30 + c = 0
c = -30
x² - x - 30 = 0
(x - 6) . (x + 5) = 0
x - 6 = 0
x = 6
(6, 0)
Jawabannya C
Kode Kategorisasi : 10.2.5
Kelas 10
Pelajaran 2 - Matematika
Bab 5 - Persamaan dan Fungsi Kuadrat