Penjelasan dengan langkah-langkah:
30] f(x) = (x + 6)² - 5
f(x) = x² + 12x + 36 - 5
f(x) = x² + 12x + 31
a = 1; b = 12; c = 31
Sumbu simetri
= x
= -b/(2a)
= -12/(2 . 1)
= -6
Jawabannya D
31] f(x) = -x² + bx - 21
a = -1; b = b; c = -21
Sumbu simetri = 5
-b/(2a) = 5
-b = 5 . 2a
-b = 5 . 2 . (-1)
-b = -10
b = 10
Jawabannya A
Kode Kategorisasi : 10.2.5
Kelas 10
Pelajaran 2 - Matematika
Bab 5 - Persamaan dan Fungsi Kuadrat
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Penjelasan dengan langkah-langkah:
30] f(x) = (x + 6)² - 5
f(x) = x² + 12x + 36 - 5
f(x) = x² + 12x + 31
a = 1; b = 12; c = 31
Sumbu simetri
= x
= -b/(2a)
= -12/(2 . 1)
= -6
Jawabannya D
31] f(x) = -x² + bx - 21
a = -1; b = b; c = -21
Sumbu simetri = 5
-b/(2a) = 5
-b = 5 . 2a
-b = 5 . 2 . (-1)
-b = -10
b = 10
Jawabannya A
Kode Kategorisasi : 10.2.5
Kelas 10
Pelajaran 2 - Matematika
Bab 5 - Persamaan dan Fungsi Kuadrat