Question

Ada yang bisa bantu???​

Answer 1

f(x) = x² + 2x + 3

a = 1

b = 2

c = 3

nilai a positif, maka kurva terbuka keatas

persamaan sumbu simetri

x = -b/2a

x = -2/2(1)

x = -2/2

x = -1

titik potong sumbu y (x = 0)

y = 0² + 2(0) + 3

y = 3

titik potong (0, 3)

jawaban B