Question

Ada yang bisa bantu???​

Answer 1

Jawab: 41. -8 atau 1 42. -3 dan 4

Penjelasan dengan langkah-langkah:

misal y+1 = x

(y+1)^2 - 3(y+1) - 10 = 0

x^2-3x-10 =0

(x+2)(x-5) = 0

(i) x + 2 = 0

y+1+2 = 0

y+3 = 0

y= -3

(ii) x-5 = 0

y+1-5 = 0

y-4 = 0

y= 4

41. 8-7x-x^2= 0

x^2 + 7x - 8 = 0

(x+8) (x-1) = 0

(i) x+8 = 0

x = -8

(ii) x-1 = 0

x = 1

Answer 2

41.

8 - 7x - x^2 = 0

(8 + x) (1 - x) = 0

8 + x = 0

x = -8

1 - x = 0

x = 1

HP : x { -8 dan 1 }

opsi : B

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42.

(y + 1)^2 - 3(y + 1) - 10 = 0

y^2 + 2y + 1 - 3y - 3 -10 = 0

y^2 - y - 12 = 0

(y - 4) (y + 3) = 0

y - 4 = 0

y = 4

y + 3 = 0

y = -3

HP : x { -3 dan 4 }

opsi : C

semoga membantu