Jawaban:
6
Penjelasan dengan langkah-langkah:
y² - 3y/2 = 2 1/2
y² - 3y/2 = 5/2
y² - 3y/2 - 5/2 = 0
dikali 2
2y² - 3y - 5 = 0
(2y - 5) . (y + 1) = 0
2y - 5 = 0
2y = 5
y = 5/2
y + 1 = 0
y = -1
y1 > y2
5/2 > -1
2y1 - y2
= 2 . 5/2 - (-1)
= 5 + 1
= 6
Kode Kategorisasi : 9.2.9
Kelas 9
Pelajaran 2 - Matematika
Bab 9 - Persamaan Kuadrat
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Jawaban:
6
Penjelasan dengan langkah-langkah:
y² - 3y/2 = 2 1/2
y² - 3y/2 = 5/2
y² - 3y/2 - 5/2 = 0
dikali 2
2y² - 3y - 5 = 0
(2y - 5) . (y + 1) = 0
2y - 5 = 0
2y = 5
y = 5/2
y + 1 = 0
y = -1
y1 > y2
5/2 > -1
2y1 - y2
= 2 . 5/2 - (-1)
= 5 + 1
= 6
Kode Kategorisasi : 9.2.9
Kelas 9
Pelajaran 2 - Matematika
Bab 9 - Persamaan Kuadrat