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n NH4CL = 0,025 mol
[OH ] = Kb ( mol basa / mol garam)
[ OH ] = 10^-5 ( 0,05 / 0,025 )
[OH ] = 2x10^-5
pOH = 5 - log 2
pH = 14 - ( 5-log 2)
pH = 9+log 2