OBLICZ :
b) 5⁷·(-5)²⁴
__________
5¹³·5¹⁸
c) (-7)¹⁰
______
7⁸·(-7)
d) (-¼)⁵:0,25²
e)(-0,1)³·0,1⁴:0,1²
f) (-0,2)³·0,2⁴·(-0,2)⁴
_________________
-(-0,2⁴·0,2⁶) NA JUTRO ; /
Acha i PROSZĘ o rozpisanie tego tak zebymsie pokapowal jak to sie robi :) pliss . PZODRAWIAM I Z GORY DZIEKUJE :)) a takie cos --> " ______" to jest kreska ułamkowa jak cos :D
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b) 5⁷·(-5)²⁴
__________ =
5¹³·5¹⁸
(-5)⁷ ⁺ ²⁴
---------- =
5¹³ ⁺ ¹⁸
(-5)³¹
-------- =
5³¹
(-5)³¹⁻³¹=
(-5)⁰ =
1
c) (-7)¹⁰
______ =
7⁸·(-7)
(-7)¹⁰
-------- =
(-7)⁸⁺¹
(-7)¹⁰
------- =
(-7)⁹
(-7)¹⁰⁻⁹ =
(-7)¹ =
-7
d) (-¼)⁵:0,25² =
(-¼)⁵ ÷( ²⁵/₁₀₀)² =-
(-¼)⁵ ÷(¼)²=
(-¼)⁵⁻² =
(-¼)³ =
-¹/⁶⁴
e)(-0,1)³·0,1⁴:0,1² =
(-0,1)³⁺⁴ ÷ 0,1² =
(-0,1)⁷ ÷ 0,1² =
(-0,1)⁷⁻² =
(-0,1)⁵
- 0,00001
f) (-0,2)³·0,2⁴·(-0,2)⁴
_________________ =
-(-0,2⁴·0,2⁶)
(-0,2)³⁺ ⁴ ⁺ ⁴
--------------- =
-(0,2⁴ ⁺ ⁶)
(-0,2)¹¹
--------- =
-0,2¹⁰
(-0,2)¹¹⁻¹⁰ =
(-0,2)¹ =
-0,2
b/ 5^7(-5)^24
-----------------= -5^31
5^13*5^18 ------- = 1
5^31
c/
(-7)^10 -7^10
--------- = ------ = -7
7^8*(-7) 7^9
d/ (-1/4)^5 :(1/4)^2 = -(1/4)^5:(/4)^ 2 = -(1/4)^3 = -1/64