a+b=32,b+c=40,c+a=26.ile wynosi a+b+c?--prosze o rozwiazanie
a+b=32
b+c=40
c+a=26
---------+
2a+2b+2c=98 /2
a+b+c=49
Odp.: Wynik to 49.
2a+2b+2c=98 /:2
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a+b=32
b+c=40
c+a=26
---------+
2a+2b+2c=98 /2
a+b+c=49
Odp.: Wynik to 49.
a+b=32
b+c=40
c+a=26
2a+2b+2c=98 /:2
a+b+c=49