a(2b-c)-b(c-2a+b)+2c(3a-b)=
=2ab-ac-bc+2ab-b²+6ac-2bc=
=4ab+5ac-3bc-b²
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a(2b-c)-b(c-2a+b)+2c(3a-b)=
=2ab-ac-bc+2ab-b²+6ac-2bc=
=4ab+5ac-3bc-b²
licze na naj