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6²+8²=10²
36+64=100
100=100, czyli trójkąt jest prostokątny.
2. B, bo z tw. Pitagorasa
7² + 12² = c2
49+144=c²
193 = c²/√
c=
3. A, z tw. Pitagorasa
5² + b² = 10²
25+b²=100
b² = 75
b =
4. B, bo
= 9
= 5
= 8
= 4
= 4
Czyli
= 4
5. A, bo
* = = 4
6.D, bo
: = = = 6
7. B, bo
4 =
czyli * = =
8. D, bo
4 =
czyli * = =
9.B, bo
lABl = = = = 5
10. D, bo
= -2
= -5
-2-2*(-5) = -2+10 = 8
Wszystko zrobione, liczę na naj ;)