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3x>5+7
3x>12
x>4
hp: { x| x>4} . hp: {5,6,7....}
3x>12
x>4
b. 6log 14 = 6log 2 + 6log 7
=(2log 2 + 2log 3)^(-1) + (7log 2 + 7log 3)^(-1)
= (1+b)^(-1) + (a+ab)^(-1)
= (a+1)/(a(b+1))