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12 g C
4,44 g H x 1 mol H = 4,44 mol H
1 g H
31,56 g Cl x 1 mol Cl =0,89 mol Cl
35,5 g Cl
se elige el menor resultado de los tres, el cual es 0,89.
C = 5,3 = 5,9 ≈6 H = 4,44 = 4,9 ≈5 Cl = 0,89 = 1
0,89 0,89 0,89
Formula Empirica = C₆H₅Cl
C= 24.74% H= 4.12 % O=32.98% N= 14.44% Na= 23.72%
24,74 g C x 1 mol C = 2.06 mol C
12 g C
4,12 g H x 1 mol H = 4, 12 mol H
1 g H
32,98 g O x 1 mol O = 2,06 mol O
16 g O
14,44 g N x 1 mol N = 1,03 mol N
14 mol N
23,72 g Na x 1 mol Na = 1,03 mol Na
23 g Na
el menor = 1,03
C = 2,06 = 2 H = 4,12 = 4 O = 2,06 = 2 N = 1,03 = 1 Na = 1,03 = 1
1,03 1,03 1,03 1,03 1,03
Formula Empirica = C₂H₄O₂NNa
porfa, calificame...gracias