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23m*4=92m
92m*2=184m
Ob=184m+23m=207m
b)
22m*2=44
58m-44m=14m
odp podstawa ma 14m
ramie: 23×4=92
Ob=23+92+92=207[cm]
B
Ob=58cm
58=22+22+x
x=58-44
x=14[cm]-podstawa
ramie---23 × 4 =92m
obw.-- 23+92+92=207m
odp. Obwód trojkata równoramiennego wynosi 207m
zad.2
58-(22×2)=58-44=14cm
podstawa ma 14cm