Question

A = ⁴log(x) dan b = ²log(x)
Jika ⁴log(b) + ²log(a) = 2, maka a+b adalah...

Answer 1

Saya nulis basisnya mirip bilangan biasa, ya.

4log(b) + 2log(a) = 2
2^2log(b) + 2log(a) = 2
(1/2) 2log(b) + 2log(a) = 2
(1/2) 2log(b) + 2*(1/2)2log(a) = 2
(1/2)(2log(b) + 2.2loga) = 2
2log(b) + 2.2log(a) = 4
2log(b) + 2log(a^2) = 4
2log(b*a^2) = 4
2^4 = b*a^2
16 = b*a^2

4log(x) = a
2log(x) = b

16 = (2log(x))*(4log(x))^2
16 = 2logx*4logx*4logx
16 = 2logx*2^2logx*2^2logx
16 = 2logx*(1/2)2logx*(1/2)2logx
16 = (1/4)(2logx)^3
64 = (2logx)^3
4 = 2logx
2^4 = x
16 = x

a = 4logx = 4log16 = 2
b = 2logx = 2log16 = 4

a + b = 2 + 4 = 6