September 2018 1 52 Report

a)  3x - 3 = 2\sqrt{2x} + 2\sqrt{2}

b) x(\sqrt{2} +3) = 2\sqrt{2} + 4x

c) 3x = 2 + \sqrt{5} +x\sqrt{5}

d) x + \sqrt{2} = \pi - 3x

e) (x + \sqrt{2})(1 - \sqrt{2}) = -1

f) (\sqrt{5} - x)(2 + \sqrt{5}) = 3\sqrt{5} + 7

Jest to zadanie ze sbioru zadań, więc mam wyniki:
a) x = 17 +12\sqrt{2}

b) x = 4 + 2\sqrt{2}

c) x = \frac{17+5\sqrt{5}}{4}

d) x = \frac{\pi-\sqrt{2}}{4}

e) x= 1

f) x = -1

Proszę pokazac jak to się oblicza, z góry dziękuję :)


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