September 2018 2 76 Report

a) (-2\sqrt{2})^2=

b) (5\sqrt[3]{2})^3=

c) (\frac{3\sqrt{5}}{2})^2=

d) (-\frac{1}{2}\sqrt{3})^2=

e) (\frac{\sqrt[3]{2}}{2})^3=

f) (\frac{\sqrt{2}}{2})^3=

g) \frac{(\frac{3}{7})^10*(\frac{14}{3})^10}{(2^3)^3}=

h)(1\frac{1}{3})^5*3^5=

i) (\frac{2}{5})^-3 / (-\frac{2}{5})^-2 \\ (chodzi \ mi \ o \ potęgi \ ujemne :))


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