A + B = 32, B + C = 40, C + A = 26. Ile wynosi A + B + C? Znajdź liczby A, B, C.
A + B=32
B+ C = 40
C+ A= 26
a= 32 - b
c= 40 - b
32 - b + 40 - b = 26 /+ 2b
72 = 26 + 2b /- 26
46 = 2b
b = 23
23 + a = 32 / -23
a = 9
c + 9 =26 / -9
c= 17
17 + 23 + 9= 49
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A + B=32
B+ C = 40
C+ A= 26
a= 32 - b
c= 40 - b
32 - b + 40 - b = 26 /+ 2b
72 = 26 + 2b /- 26
46 = 2b
b = 23
23 + a = 32 / -23
a = 9
c + 9 =26 / -9
c= 17
17 + 23 + 9= 49