a= 3log₈4, zatem a jest równe...
Wartością wyrażenia (3-√5)² jest liczba..
a= 3log₈4 = log₈ 4^3 = log₈ 64 = log₈ 8^2 = 2 * log₈ 8 = 2 * 1 = 2
(3-√5)²= 3² - 2 * 3 * √5 + √5² = 9 - 6√5 + 5 = 14 - 6√5
1. log₈4³=log₈64=2 bo
8²=64 a=2
2.(3-√5)²=
9-6√5+5=
14-6√5
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a= 3log₈4 = log₈ 4^3 = log₈ 64 = log₈ 8^2 = 2 * log₈ 8 = 2 * 1 = 2
(3-√5)²= 3² - 2 * 3 * √5 + √5² = 9 - 6√5 + 5 = 14 - 6√5
1. log₈4³=log₈64=2 bo
8²=64 a=2
2.(3-√5)²=
9-6√5+5=
14-6√5