Question

(a-2b)*(b+1)-3a*(a+b-2)-(7a-2b'2)=?? dla a=-2 b=-1

* '2 = to oznacza do potęgi drugiej

Answer 1

(a - 2b)(b + 1) - 3a(a + b - 2) - (7a - 2b²) = ab + a - 2b² - 2b - 3a² - 3ab + 6a - 7a + 2b²
= -2ab - 3a² - 2b

a = -2, b = -1

-2*(-2)*(-1) - 3*(-2)² - 2*(-1) = -4 - 12 + 2 = -14