Question

A)-(2a`-3ab)-(2b-3a`)+(-ab-b)
b)(x`+1)-(x`-2)+10
c)(a+4b)-(5+2a)-(3b-5)
` to jest kwadrat, czyli 2a kwadrat itp

Answer 1

A)-(2a`-3ab)-(2b-3a`)+(-ab-b)= -2a'+3ab-2b+3a'-ab-b=a'+2ab-3b
b)(x`+1)-(x`-2)+10= x'+1-x'+2+10=13
c)(a+4b)-(5+2a)-(3b-5)= a+4b-5-2a-3b+5= -a+b

Answer 2

-(2a²-3ab)-(2b-3a²)+(-ab-b)=-2a²+3ab-2b+3a²-ab-b=a²+2ab-3b

(x²+1)-(x²-2)+10=x²+1-x²+2+10=13

(a+4b)-(5+2a)-(3b-5)=a+4b-5-2a-3b+5=-a+b