9^x+1 +3=28*3^x
wiem tylko że wyniki to x=-2 i x=1 proszę o pomoc
(9^(x+1))+3=28*3^x
(3^(2(x+1)))-28*3^x+3=0
(9*3^2x)-(28*3^x)+3=0
3^x=z
9z^2-28z+3=0
delta=784-108=676
delta pod pierwiastkiem=26
z1=(26+28)/18=3
z2=(-26+28)/18=1/9
3^x=3 lub 3^x=1/9
3^x=3^1 lub 3^x=3^(-2)
x=1 lub x=-2
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(9^(x+1))+3=28*3^x
(3^(2(x+1)))-28*3^x+3=0
(9*3^2x)-(28*3^x)+3=0
3^x=z
9z^2-28z+3=0
delta=784-108=676
delta pod pierwiastkiem=26
z1=(26+28)/18=3
z2=(-26+28)/18=1/9
3^x=3 lub 3^x=1/9
3^x=3^1 lub 3^x=3^(-2)
x=1 lub x=-2