9.Diketahui sistem persamaan sebagai berikut a – 2b + 3c = 10 2a – b –c = 3 3a – 3b -2c = 5 Nilai dari a + b + c adalah
Gunakan metode Eliminasi Subtitusi (Gabungan)
whongaliema - 2b + 3c = 10 ...... pers I 2a - b - c = 3 ....... pers II 3a - 3b - 2c = 5 ........pers III
elemenasi pers I dan II a - 2b + 3c = 10 ... | kali 1 | ⇒ a - 2b + 3c = 10 2a - b - c = 3 ....... | kali 3 | ⇒ 2a - 3b - 3c = 9 -------------------------- + 3a - 5b = 19 .... pers IV
elemenasi pers II dan III 2a - b - c = 3 ...... | kali 2 | ⇒ 4a - 2b - 2c = 6 3a - 3b - 2c = 5 ....| kali 1 | ⇒ 3a - 3b - 2c = 5 ------------------------- - a + b = 1 ... pers V
elemenasi pers IV dan V 3a - 5b = 19 ..... | kali 1 | ⇒ 3a - 5b = 19 a + b = 1 .......| kali 5 | ⇒ 5a + 5b = 5 ---------------------- + 8a = 24 a = 24/8 a = 3 a + b = 1 3 + b = 1 b = 1 - 3 b = - 2
2a - b - c = 3 ....... pers II
3a - 3b - 2c = 5 ........pers III
elemenasi pers I dan II
a - 2b + 3c = 10 ... | kali 1 | ⇒ a - 2b + 3c = 10
2a - b - c = 3 ....... | kali 3 | ⇒ 2a - 3b - 3c = 9
-------------------------- +
3a - 5b = 19 .... pers IV
elemenasi pers II dan III
2a - b - c = 3 ...... | kali 2 | ⇒ 4a - 2b - 2c = 6
3a - 3b - 2c = 5 ....| kali 1 | ⇒ 3a - 3b - 2c = 5
------------------------- -
a + b = 1 ... pers V
elemenasi pers IV dan V
3a - 5b = 19 ..... | kali 1 | ⇒ 3a - 5b = 19
a + b = 1 .......| kali 5 | ⇒ 5a + 5b = 5
---------------------- +
8a = 24
a = 24/8
a = 3
a + b = 1
3 + b = 1
b = 1 - 3
b = - 2
a - 2b + 3c = 10
3 - 2 (- 2) + 3c = 10
3 + 4 + 3c = 10
7 + 3c = 10
3c = 10 - 7
3c = 3
c = 3/3
c = 1
a + b + c = 3 + (- 2) + 1
= 2