Proezę o rozwiązanie zadania :D(proszę o obliczenia jeśli takie będą)
a)√2 * √4½
b)∛2⅔ * ∛1/9
c)∛-9 * ∛3
a) 3
b) 2/3
c) -3
a) √2 * √4½ = √2 * 4.5 = √9 = 3
b) 2⅔ * 1/9 = 8/3 * 1/9 = 8/27
c ) -9 * 3 = - 27
a)√2 * √4½===3
b)∛2⅔ * ∛1/9==\sqrt[3]{0,25}
c)∛-9 * ∛3=-9*3=-27
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a) 3
b) 2/3
c) -3
a) √2 * √4½ = √2 * 4.5 = √9 = 3
b) 2⅔ * 1/9 = 8/3 * 1/9 = 8/27
c ) -9 * 3 = - 27
a)√2 * √4½===3
b)∛2⅔ * ∛1/9==\sqrt[3]{0,25}
c)∛-9 * ∛3=-9*3=-27