9 do potęgi log3 16. prosze o uzasadnienie
9^log3 16 = (3^2)^log 3 16 = 3^2log3 16 = 3^log3 256 = 256
a^loga b = b
alogb c = logb c^a
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9^log3 16 = (3^2)^log 3 16 = 3^2log3 16 = 3^log3 256 = 256
a^loga b = b
alogb c = logb c^a