Question

9 do potegi jednej trzeciej razy 27 do potegi jednej drugiej dzielone przez pierwiastek z 3

Answer 1

9^(1/3) x 27^(1/2)      (3^2)^(1/3) x (3^3)^(1/2)     3^(2/3) x 3^(3/2)

----------------------- = -------------------------------- = -------------------- =

          √3                                  3^(1/2)                     3^(1/2)

 

 

3^(2/3 + 3/2) : 3^(1/2) = 3^(4/6 + 9/6) : 3^(1/2) = 3^(13/6) : 3^(3/6) = 3^(13/6 - 3/6) = 3^(10/6) = 3^(5/3) = ∛3^5 = ∛(3^3 x 3^2) = ∛3^3 x ∛3^2 = 3 ∛9