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|a| ≥ b ⇔ a≤-b V a≥b
Entonces:
|x/9| ≥ 1 ⇔ x/9 ≤ -1 V x/9 ≥ 1
x ≤ -9 x≥9
S1: (-∞,-9) S2:(9,+∞)
S=S1 U S2
Solución=S= (-∞,-9) U (9,+∞)
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