Question

Oblicz pamiętając o kolejności wykonywania działań:
a)2i1/5X10+1i3/4
2/3X1i4/5+2i1/2
b)3i3/4+2i2/3X2i1/4
[(1i1/2)potęga2+1i1/6]X3
c)2i2/5X1i2/3-1i5/6
4i7/8-1i1/3X1i1/8
Proszę pomóżcie daję naj

Answer 1

A) (2 1/5) * 10 + 1 3/4 = (11/5)*10-1 3/4 = 11*2+1 3/4 = 22 + 1 3/4 = 23 3/4
2/3*4/5+2 1/2 = 8/15 + 2 1/2 = 2 31/30 = 3 1/30

b) 3 3/4 + 2 2/3 * 2 1/4 = 3 3/4 + 8/3*9/4 = 3 3/4 + 2*3=3 3/4+6=9 3/4
[(1 1/2)^2]+1 1/6)*3 = [(3/2)^2+1 1/6]^3 = (9/4+1 1/6)*3 = 1 58/24 = 3 6/24 = 3 1/4

c) (2 2/5)*(1 2/3)-1 5/6 = 12/5*5/3-1 5/6 = 4-1 5/6 = 3 6/6 - 1 5/6 = 2 1/6
4 7/8 - 1 1/3*1 1/8 = 4 7/8 - 4/3 * 9/8 = 4 7/8 - 3/2 = 4 7/8 - 1 1/2 = 4 7/8 - 1 4/8 = 3 3/8