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a = 4/2 = 2, b= -4/2 = -2, S1(2, -2), r² = a² + b² - c = 4 + 4 -7 = 1 ----> r = 1
O2: x² + 4x + y² + 6y - 23 = 0
a = -4/2 = -2, b = -6/2 = -3, S2(-2, -3) , r² = a² + b² - c = 4 +9 +23 = 36 ---> r = 6
Rysujemy oba okręgi (załącznik) i widać że O1 leży wewnątrz O2.