Question

Log100 + log4 1/8

Answer 1

log100+log₄1/8

 

def

loga b=x  ->  a^x=b

 

log100=2;   10²=100

 

log₄1/8=x;  4^x=1/8;    2^(2x)=2^(-3);  2x=-3;   x=-3/2

log₄1/8=-3/2

 

log100+log₄1/8=2-3/2=1/2