∫(x/(8+25x²) dx = Usamos sustitución u=8+25x² du= 50x dx du/50 = x dx ∫(1/u 1/50 du) = 1/50 × ∫(1/u du) = 1/50 × ( ln |u| + c) = 1/50 × ln (8+25x²) = Rta: [ln (8+25x²)]/50
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∫(x/(8+25x²) dx = Usamos sustitución u=8+25x² du= 50x dx du/50 = x dx ∫(1/u 1/50 du) = 1/50 × ∫(1/u du) = 1/50 × ( ln |u| + c) = 1/50 × ln (8+25x²) = Rta: [ln (8+25x²)]/50