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Verified answer
9^(3x+2) > 1/[81^(2x-5)]9^(3x+2) > 1/[9^2(2x-5)]
9^(3x+2) > 1/[9^(4x-10)]
[9^(3x+2)][ 9^(4x+10)] > 1
[9^(3x+2)][ 9^(4x+10)] > 9^0
9^[3x + 2 + 4x + 10] > 9^0
3x + 2 + 4x + 10 > 0
7x + 12 > 0
7x > -12
x < -12/7 (tanda > berubah menjadi < karena adanya pembagian dengan bilangan negatif)